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A wire having a linear density of 0.05 k...

A wire having a linear density of 0.05 kg/m is stretched between two rigid supports. The tension in the wire is `4.5xx10^7` dyne . If the observed that the wire resonates at a frequency of 420 Hz and the next higher frequency at which the wire resonates is 490 Hz, then the length of the wire would be

A

75 cm

B

21.4 cm

C

214m

D

114m

Text Solution

Verified by Experts

The correct Answer is:
C
`n=n_2-n_1 = (1)/(2l) sqrt(T/m)`
`70=(1)/(2l) sqrt((4.5xx10^7)/(0.05))`
`therefore l=(1)/(140)3xx10^4 = 214.2cm`
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