The linear density of a vibrating string is `1.3 xx 10^(-4) kg//m` A transverse wave is propagating on the string and is described by the equation `y= 0.021 sin (x + 30 t)` where x and y are measured in meter and t`t` in second the tension in the string is :-

Options

A. 0.48 N
B. 1.20 N
C. 0.117 N
D. 4.8 N

Answer

C

Explanation

`omega = 30 therefore 2pin = 30 therefore n=(15)/(pi)`
`K=1 therefore (2pi)/(lamda) =1 therefore lamda = 2pi`
`v=nlamda = (15)/(pi) xx2pi = 30m//s`
`v=sqrt(T/m) therefore v^2=T/m`
`therefore T=v^2m = 30xx30xx1.3xx10^(-4) = 0.177 N`