A string of length 0.5m and linear densi...

A string of length 0.5m and linear density `10^(-4)` kg/m is stretched under a tension of 100 N. If the frequency of the vibration of the string is 4000 Hz, how many loops are formed on the string?

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The correct Answer is:

`n=(P)/(2l) sqrt(T/m) therefore P=(4000xx2xx0.5)/(10^3)=4`

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