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A steel wire of length 1m is stretched b...

A steel wire of length 1m is stretched between two rigid supports. The wire is vibrating in its fundamental mode with a frequency 100 Hz. The maximum acceleration at the mid point of the wire is 986 `m//s^2` . Then the amplitude of vibration at the midpoint is

A

25 cm

B

0.5 cm

C

0.25 cm

D

50 cm

Text Solution

Verified by Experts

The correct Answer is:
C
`a_m = omega^2A therefore A=(a_m)/(omega^2)`
= `(986)/(4pi^2xx100xx100) = (9.86xx100)/(4xxpi^2xx 100xx100)`
=0.25cm
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