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The radius of stretched sring is decreas...

The radius of stretched sring is decreased by 1% . Then the change in fundamental frequency

A

Decrease by 1%

B

Increase by 2%

C

Increase by 1%

D

Decrease by 1%

Text Solution

Verified by Experts

The correct Answer is:
C
`(Deltam)/(n) = (Deltar)/( R) = ` + 1% = increases by 1%
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