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An open pipe resonates to a fundamental...

An open pipe resonates to a fundamental frequency 300 Hz and closed pipe to a fundamental frequency 150Hz. If they are joined to form a longer closed tube, then the fundamental frequency of resonance will be

A

72Hz

B

75Hz

C

45Hz

D

47Hz

Text Solution

Verified by Experts

The correct Answer is:
B
`n=(n_1n_2)/(2n_2n_1)=(300xx150)/(300+300) = (300xx150)/(600) = 75`
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