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An open tube resonates to a frequency of...

An open tube resonates to a frequency of 156 Hz. When it is dipper so that `(1//4)^(th)` of its length is under water , to what frequency does it resonate ?

A

150.6Hz

B

160.6Hz

C

170.6Hz

D

180.6Hz

Text Solution

Verified by Experts

The correct Answer is:
C
`n_0 = (v)/(2l)`
`n_1=(v)/(4l_1) = (v)/(4(3/4l))`
`n_1=(v)/(3l)`
`n_1/n_0 = (v)/(3l)xx(2l)/(v)=2/3`
`n_1=2/3n_0=2/3xx256`
`n_1=512/3 = 170Hz.`
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