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Tension applied to a wire of length 1m a...

Tension applied to a wire of length 1m and its mass 1g, if it is to vibrate with the fundamental frequency of 50 Hz, will be

A

100N

B

10N

C

50N

D

2.5N

Text Solution

Verified by Experts

The correct Answer is:
B
`m=(m')/(l) = (10^(-3))/(1) therefore n=(1)/(2l) sqrt(T/m)`
`therefore T=4l^2n^2m=4xx1xx2500xx10^(-3)=10N`
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