If the length of a closed organ pipe is ...

If the length of a closed organ pipe is 1m and velocity of sound is 330 m/s , then the frequency for the second note is

`4xx330/4Hz`

`3xx330/4Hz`

`2xx330/4Hz`

`2xx4/330Hz`

Text Solution

Verified by Experts

The correct Answer is:

`n_c = (v)/(4l) = (330)/(4xx1) = 330/4`
`n_1 = 3n_c = (3xx330)/(4)`

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