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A stationary wave incident on rigid wall...

A stationary wave incident on rigid wall. Then the distance between wall and first antinode is (velocity of wave is 36 m/s and frequency 72Hz)

A

1/2m

B

1/4m

C

1/8m

D

1m

Text Solution

Verified by Experts

The correct Answer is:
C
`lamda = v/n`
`lamda/4 = (v)/(4n)`
`=(36)/(4xx72)`
`lamda/4 = 1/8 m`
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