If the pressure at half the depth of a tank is equal to `2/3` the pressure at the bottom of the tank, then the height of the water column in the tank is
`("Atmospheric pressure "=10^5N//m^2`)

Options

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Answer

B

Explanation

`P_(h)=(2)/(3)P_(b)`
`P_(0)+(h rhog)/(2)=(2)/(3)[h rhog+P_(0)]`
`(P_(0))/(3)=h rhog[(4-3)/(6)]`
`(P_(0))/(3)=(h rho g)/(6)`
`P_(0)=(h rho g)/(2)`
`h rho g =2xx10^(5)`
`h=(2xx10^(5))/(10^(3)xx10)=20m`.