What will be the rms speed f argon at `40^(@)C`? If the rms speed of oxygen molecule at 1092 K is 920 /s. (molecular weight of oxygen is 32 and that of argon is 40).

Options

A. 460 m/s
B. 404.5 m/s
C. 44 m/s
D. 4405.0 m/s

Answer

A

Explanation

`(C_(2))/(C_(1))=sqrt((T_(2))/(T_(1))xx(M_(1))/(M_(2)))=sqrt((313xx32)/(1092xx40))`
`=sqrt((313)/(1092)xx(4)/(5))=sqrt((313)/(273)xx(1)/(5))`
`C_(2)=(920)/(2)=460m//s`.