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If the density of the gas at NTP is 0.17...

If the density of the gas at NTP is 0.178 `km//m^(3)`, then the R.M.S. velocity of the molecules of a gas at N.T.P. will be `(P_(0)=10^(5)N//m^(2))`

A

1306 m/s

B

13.06 km/s

C

130.6 km/s

D

1340 m/s

Text Solution

Verified by Experts

The correct Answer is:
A
`C_(rms)=sqrt((3P)/(rho))=sqrt((3xx10^(5))/(0.178))=sqrt((3xx108)/(178))`
=1308 m/s.
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