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The temperature at which rms velocities ...

The temperature at which rms velocities of nitrogen gas molecules will be doulbed that at `0^(@)C` is

A

273 K

B

546 K

C

136 K

D

1092 K

Text Solution

Verified by Experts

The correct Answer is:
D
`C_(1)propsqrt(T_(1)) and C_(2) prop sqrt(T_(2))(C_(2))/(C_(1))=sqrt((T_(2))/(T_(1)))`
`therefore T_(2)=(C_(2)^(2))/(C_(1)^(2))T_(1)`
`=4xx273=1092K`
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