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The temperature at which the r.m.s. velo...

The temperature at which the r.m.s. velocity of oxygen molecules equal that of nitrogen molecules at `100^(@)C` is nearly.

A

42.63 K

B

426.3 K

C

4263 K

D

4.263 K

Text Solution

Verified by Experts

The correct Answer is:
B
`V_(n)=V_(o)`
`sqrt((3RT_(n))/(M_(n)))=sqrt((3RT_(o))/(M_(o)))`
`(T_(o))/(T_(n))=(M_(o))/(M_(n))`
`T_(o)=373xx(32)/(28)=426.3K`
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