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The average translational energy and the rms speed of molecules in a sample of oxygen gas at `300K` are `6.21xx10^(-21)J` and `484m//s`, respectively. The corresponding values at `600K` are nearly (assuming ideal gas behaviour)

A

`12.42xx10^(-21)J,968m//s`

B

`8.78xx10^(-21)J,684m//s`

C

`6.21xx10^(-21)J,968m//s`

D

`12.42xx10^(-21)J,684m//s`

Text Solution

Verified by Experts

The correct Answer is:
D

`(C_(2))/(C_(1))=sqrt((T_(2))/(T_(1)))=sqrt((600)/(300))=sqrt(2)`
`C_(2)=1.414xx484=684m//s`
`(KE_(2))/(KE_(1))=(T_(2))/(T_(1))=(600)/(300)=2`
`K.E_(2)=2K.E_(1)`
`=2xx6.21xx10^(-21)=12.42xx10^(21)J`
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