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Mean kinetic energy per gram mole of an ...

Mean kinetic energy per gram mole of an ideal gas at `0^(@)C` is nearly `(R=8.320J//gm" mol"xxK)`

A

3.4 J

B

3.4 J

C

340 J

D

3400J

Text Solution

Verified by Experts

The correct Answer is:
D
`(KE_(2))/(gm)=(3)/(2)RT=1.5xx8.320xx273=3400J`
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