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What is the K.E. of translational motion...

What is the K.E. of translational motion of molecules in 15 gram of ammonia gas at `37^(@)C`? (Molecular weight of ammonia is 17.03 and R=8.31 J/mol K)

A

3404 J

B

340.3 J

C

401.5 J

D

4090 J

Text Solution

Verified by Experts

The correct Answer is:
A
`K.E.=(3)/(2)(RT)/(M)m=(1.5xx8.21xx310xx15xx10^(-3))/(17.03xx10^(-3))=3403J`
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