The density of oxygen at N.T.P. is `16xx0.089kg//m^(3)` then the R.M.S. velocity of oxygen molecules at N.T.P. would be

Options

A. `4.6xx10^(2)m//s`
B. `46xx10^(2)m//s`
C. `0.46xx10^(2)m//s`
D. `3.6xx10^(2)m//s`

Answer

A

Explanation

`C=sqrt((3P)/(rho))=sqrt((3xx10^(5))/(16xx90xx10^(-3)))`
`C=sqrt((3xx10^(7))/(16xx93))=sqrt((10xx10^6)/(16xx3))=sqrt((3.33)/(16)xx10^(6))`
`=(1.8xx10^(3))/(4)=0.45xx10^(3)=450m//s`.