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If the specific heat of lead is 0.03 cal...

If the specific heat of lead is 0.03 cal/gm, then the thermal capacity of 500 gm of lead will be

A

`5cal//.^(@)C`

B

`10cal//.^(@)C`

C

`15cal//.^(@)C`

D

`20cal//.^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
`C=mc=500xx0.03=15cal//.^(@)C`
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