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If R is the molar gas constant and gamma...

If R is the molar gas constant and `gamma=C_(P)//C_(V),` then `C_(p)` is equal to

A

`R//gamma`

B

`gammaR`

C

`(2R)/(gamma-1)`

D

`(Rgamma)/(gamma-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`C_(p)=C_(V)+R=(R)/(gamma+1)+R`
`=R[(1)/(gamma-1)+1]=R[(1+gamma-1)/(gamma-1)]=(gammaR)/(gamma-1)`
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