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At a constant pressure of 20 Pa a gas is...

At a constant pressure of 20 Pa a gas is compressed from 10 `m^(3)` to 5 `m^(3)`. Later 100 J of heat is added to the system. The change in internal energy is

A

200 J

B

400 J, 260 J

C

300 J

D

100 J

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaW=P(V_(2)-V_(1))=20(5-10)=-100J`
`DeltaQ=100J`
`DeltaQ=DeltaU+DeltaW`
100=`DeltaU-100implies DeltaU=200J`
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