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At a constant pressure of 20 Pa a gas is...

At a constant pressure of 20 Pa a gas is compressed from 10 `m^(3)` to 5 `m^(3)`. Later 100 J of heat is added to the system. The change in internal energy is

A

100 J

B

200 J

C

300 J

D

400 J

Text Solution

Verified by Experts

The correct Answer is:
B
`d_(omega)=PDeltaV=20xx(V_(2)-V_(1))`
`=20xx(5-10)=20xx-5=-100J`
`dQ=du+domega`
`therefore du=dQ-domega`
=100+100=200J.
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