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A carnot engine takes 300 cal. of heat ...

A carnot engine takes 300 cal. of heat at 500 k and rejects 150 cal of heat to the sink. The temperature (in k) of sink is __________.

A

1000 K

B

750 K

C

250 K

D

125 K

Text Solution

Verified by Experts

The correct Answer is:
C
`eta=(W)/(Q)=1-(T_(2))/(T_(1))`
`therefore (T_(2))/(T_(1))=(Q-W)/(Q)`
`T_(2)=500(150)/(300)=250K`.
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