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The absolute temperatures of two black b...

The absolute temperatures of two black bodies are 2000 K and 3000 K respectively. The ratio of wavelengths corresponding to maximum emission of radiation by them will be

A

`2:3`

B

`3:2`

C

`9:4`

D

`4:9`

Text Solution

Verified by Experts

The correct Answer is:
B

`lamda_(m)T=lamda_(m)'T'`
`therefore (lamda_(m))/(lamda_(m)')=(T')/(T)=(3000)/(2000)=(3)/(2)`
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