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The maximum energy in thermal radiation ...

The maximum energy in thermal radiation from a source occurs at the wavelength 4000Å. The effective temperature of the source

A

7000 K

B

80000 K

C

`10^(4)K`

D

`10^(6)K`

Text Solution

Verified by Experts

The correct Answer is:
A
`lamda_(m)=(b)/(T) " "therefore T=(b)/(lamda_(m))=(2.93xx10^(-3))/(4000xx10^(-10))=7325K`.
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