A black body at high temperature `T` `K` radiates energy at the rate of `E W//m^(2)`. When the temperature falls to `(T//2) K`, the radiated energy will be

Options

A. E/16
B. E/4
C. E/2
D. 16 E

Answer

A

Explanation

`(E_(2))/(E_(1))=((T_(2))/(T_(1)))^(4)=(((T)/(2))/(T))^(4)=(1)/(16)`
`therefore E_(2)=(E)/(16)`.