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The rate of loss of heat by radiation fr...

The rate of loss of heat by radiation frombody at `400^(@)C` is R. then radiation from it when the temperature of the ball is `627^(@)C`. Then the rate of loss of heat per unit area will be

A

2R

B

4R

C

3/16 R

D

16/3 R

Text Solution

Verified by Experts

The correct Answer is:
D
`(R_(2))/(R_(1))=((T_(2))/(T_(1)))^(4)=((1073)/(673))^(4)=(1.5)^(4)=(81)/(16)=5`
`R_(2)=5R`.
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