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A 60 w bulb has a filament temperature o...

A 60 w bulb has a filament temperature of 2000 K. what will be the wattage of another bulbs of same filament area and material at a temperature of 4000 K?

A

8 w

B

32 w

C

64 w

D

960 w

Text Solution

Verified by Experts

The correct Answer is:
D
`(P_(2))/(P_(1))=(T_(2)^(4))/(T_(1)^(4))=((4000)/(2000))^(4)=16`
`P_(2)=16xxP_(1)=16xx60=960w`
`P=sigma A rhoT^(4)`
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