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The thermal capacities of two bodies A a...

The thermal capacities of two bodies A and B are in the ratio 1:4. if the rate of heat loss are equal for these two bodies then the rate of fall of the temperature will be in the ratio

A

`1:1`

B

`1:4`

C

`4:1`

D

`(4)^(1//4):1`

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the relationship between the thermal capacities of two bodies and their rates of temperature change. Here’s a step-by-step solution: ### Step 1: Understand the given information The thermal capacities of two bodies A and B are in the ratio 1:4. This means if we denote the thermal capacity of body A as \( C_A \) and that of body B as \( C_B \), we can write: \[ C_A : C_B = 1 : 4 \] This implies: \[ C_A = k \quad \text{and} \quad C_B = 4k \] for some constant \( k \). ### Step 2: Relate heat loss to temperature change According to the principle of heat transfer, the rate of heat loss \( \frac{dQ}{dt} \) for each body can be expressed as: \[ \frac{dQ}{dt} = -C \frac{dT}{dt} \] where \( C \) is the thermal capacity and \( \frac{dT}{dt} \) is the rate of fall of temperature. ### Step 3: Set up the equations for both bodies For body A: \[ \frac{dQ_A}{dt} = -C_A \frac{dT_A}{dt} \] For body B: \[ \frac{dQ_B}{dt} = -C_B \frac{dT_B}{dt} \] Since the rate of heat loss is equal for both bodies, we can set these equations equal to each other: \[ -C_A \frac{dT_A}{dt} = -C_B \frac{dT_B}{dt} \] ### Step 4: Substitute the thermal capacities Substituting the values of \( C_A \) and \( C_B \): \[ -k \frac{dT_A}{dt} = -4k \frac{dT_B}{dt} \] We can cancel \( -k \) from both sides (assuming \( k \neq 0 \)): \[ \frac{dT_A}{dt} = 4 \frac{dT_B}{dt} \] ### Step 5: Find the ratio of the rates of fall of temperature Rearranging the equation gives: \[ \frac{dT_A}{dT_B} = 4 \] This means that the rate of fall of temperature for body A is 4 times that of body B. Therefore, the ratio of the rates of fall of temperature (which we denote as \( R_A : R_B \)) is: \[ R_A : R_B = 4 : 1 \] ### Final Answer The rate of fall of the temperature will be in the ratio \( 4 : 1 \). ---
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