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If the temperature of a body is reduced ...

If the temperature of a body is reduced to half of in initial temperature, then radiation power decresed by

A

0.84

B

0.94

C

0.06

D

0.16

Text Solution

Verified by Experts

The correct Answer is:
B

`(P_(2))/(P_(1))=((T_(2))/(T_(1)))^(4)=(((T)/(2))/(T))^(4)`
`(P_(2))/(P_(1))=(1)/(16)`
`(P_(2)-P_(1))/(P_(1))=(1-16)/(16)=-(15)/(16)=93.75%=94%`.
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