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A body takes, 4 minutes to cool from 100...

A body takes, 4 minutes to cool from `100^(@)C` to `70^(@)C`, if the room temperature is `25^(@)C`, then the time taken to cool from `70^(@)C` to `40^(@)C` will be

A

10 minute

B

3 minute

C

6 minute

D

8 minute

Text Solution

Verified by Experts

The correct Answer is:
D
`(d theta)/(dt)=k(theta_(AV)-theta_(0))`
`(30)/(4)=k(85-25)`
`(30)/(dt)=k(55-25)`
`dt=8`
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