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A body cools from 60^(@)C to 52^(@)C in ...

A body cools from `60^(@)C` to `52^(@)C` in five minutes. What will be further fall in temperature in the next five minutes? If the temperature of the surrounding is `28^(@)C`

A

`4^(@)C`

B

`6^(@)C`

C

`8^(@)C`

D

`2^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
B
`((d theta)/(dt))=k(theta_(AV_-theta_(0))`
`(8)/(5)=k(56-28)` .. . (i)
`(52-theta)/(5)=k((52+theta)/(2)-28)` . . . (ii)
`(52-theta)/(8)=((52+theta-56))/(2xx28)`
`theta=46`
`d theta=52-46=6^(@)C `
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NIKITA PUBLICATION-KINETIC THEORY OF GASES & RADIATION -MCQs (Newtons Law of Cooling)
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