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The wavelength of maximum energy release...

The wavelength of maximum energy released during an atomic axplosion was `2.93xx10^(-10)m`. Given that Wien's constant is `2.93xx10^(-3)m-K`, the maximum temperature attained must be of the order of

A

`5.86xx10^(7)K`

B

`10^(-13)K`

C

`10^(-7)K`

D

`10^(7)K`

Text Solution

Verified by Experts

The correct Answer is:
D
`T=(b)/(lamda)=(2.93xx10^(-3))/(2.93xx10^(-10))=10^(7)K`.
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