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The ratio of energy of emitted radiation...

The ratio of energy of emitted radiation of a black body at `27^(@)C` and `927^(@)C` is

A

`1:4`

B

`1:16`

C

`1:8`

D

`1:256`

Text Solution

Verified by Experts

The correct Answer is:
D
`(E_(1))/(E_(2))=((T_(1))/(T_(2)))^(4)=((300)/(1200))^(4)=((1)/(4))^(4)=(1)/(256)`.
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