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The observer is moving with velocity 'v'...

The observer is moving with velocity `'v'_(0)` towards the stationary source of sound and then after crossing moves away from the source with velocity `'v'_(0)`. Assume that the medium through which the sound waves travel is at rest. If v is the velocity of sound and n is the frequency emitted by the source, then the difference between appearent frequencies heard by the observer is

A

`(2n v_(0))/(v)`

B

`(n v_(0))/(v)`

C

`(v)/(2n v_(0))`

D

`(v)/(n v_(0))`

Text Solution

Verified by Experts

The correct Answer is:
A
`v'=v(v+v_(0)/(v))`
`v''=v(v-v_(0)/(v))`
`v'-v'=v/v (v+v_(0)-v+v_(0))`
`=(2v v_(0))/(v)`
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Knowledge Check

  • An observer is moving towards the stationary source of sound, then

    A
    Apparent frequency will be less than the real frequency
    B
    Apparent frequency will be greater than the real frequency
    C
    Apparent frequency will be equal to real frequency
    D
    Only the quality of sound will change

  • If an observer moving with velocity v crosses a stationary source of frequency n, then the change in the frequency would be -

    A
    `(2n(V^(2)+v^(2)))/(V v)`
    B
    `(2n(V^(2) - v^(2)))/(v v)`
    C
    `(2nV)/(v)`
    D
    `(2nv)/(V)`

  • An observer A is moving directly towards a stationary sound source while another observer B is moving away from the source with the same velocity. Which of the following statements are correct?

    A
    Average of freqeuncies recorded by `A` and `B` is equal to natural frequency of the source
    B
    Wavelength of wave received by `A` is less than that of waves received by `B`.
    C
    Wavelength of waves received by two observers will be same.
    D
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