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The observer is moving with velocity 'v'...

The observer is moving with velocity `'v'_(0)` towards the stationary source of sound and then after crossing moves away from the source with velocity `'v'_(0)`. Assume that the medium through which the sound waves travel is at rest. If v is the velocity of sound and n is the frequency emitted by the source, then the difference between appearent frequencies heard by the observer is

A

`(2n v_(0))/(v)`

B

`(n v_(0))/(v)`

C

`(v)/(2n v_(0))`

D

`(v)/(n v_(0))`

Text Solution

Verified by Experts

The correct Answer is:
A
`v'=v(v+v_(0)/(v))`
`v''=v(v-v_(0)/(v))`
`v'-v'=v/v (v+v_(0)-v+v_(0))`
`=(2v v_(0))/(v)`
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