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The polarising angle the transparent m...

The polarising angle the transparent medium is `'theta'` and 'v' is the speed of light in that medium. Then the relation between `'theta'` and 'v' is
(c = velocity of light in air)

A

`theta=tan^(-1) ((v)/(c))`

B

`theta=cot^(-1) ((v)/(c))`

C

`theta=sin^(-1) ((v)/(c))`

D

`theta=cos^(-1)((v)/(c))`

Text Solution

Verified by Experts

The correct Answer is:
B
`therefore tan theta=mu=(C)/(V)`
`therefore cot theta=(V)/(C)`
`therefore theta=cot^(-1) ((V)/(C))`
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Knowledge Check

  • The speed of light in the medium is

    A
    minimum on the axis of the beam
    B
    the same everywhere in the beam
    C
    directly proportional to the intensity
    D
    maximum on the axis of the beam

  • Speed of light in a medium depends on

    A
    inertial properties of the medium
    B
    elastic properties of the medium
    C
    inertial as well as elastic properties of the medium
    D
    neither inertial nor elastic properties of the medium

  • Polarising angle of a transparent medium is 60^(@) , angle of refraction will be

    A
    `120^(@)`
    B
    `45^(@)`
    C
    `30^(@)`
    D
    `60^(@)`

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