Home
Class 12
PHYSICS
The polarising angle the transparent m...

The polarising angle the transparent medium is `'theta'` and 'v' is the speed of light in that medium. Then the relation between `'theta'` and 'v' is
(c = velocity of light in air)

A

`theta=tan^(-1) ((v)/(c))`

B

`theta=cot^(-1) ((v)/(c))`

C

`theta=sin^(-1) ((v)/(c))`

D

`theta=cos^(-1)((v)/(c))`

Text Solution

Verified by Experts

The correct Answer is:
B

`therefore tan theta=mu=(C)/(V)`
`therefore cot theta=(V)/(C)`
`therefore theta=cot^(-1) ((V)/(C))`
Promotional Banner

Topper's Solved these Questions

  • MH-CET - 2017

    NIKITA PUBLICATION|Exercise INTERFERENCE AND DIFFRACTION|3 Videos
  • MH-CET - 2017

    NIKITA PUBLICATION|Exercise ELECTROSTATICS|3 Videos
  • MH-CET - 2017

    NIKITA PUBLICATION|Exercise KINETIC THEORY OF GASES & RADIATION|3 Videos
  • MCQS FROM BOARD EXAM

    NIKITA PUBLICATION|Exercise COMMUNICATION SYSTEMS|7 Videos
  • MHT-CET 2016

    NIKITA PUBLICATION|Exercise COMMUNICATION SYSTEMS|1 Videos

Similar Questions

Explore conceptually related problems

The speed of light in the medium is

Speed of light in a medium depends on

Does the polarizing angle e, for a transparent medium depend upon the wavelength of light?

The absolute refractive index of a transparent medium is 5/3. Find the speed of light in the medium.

The absolute refractive index of a transparent medium is 5//3 . Find the speed of light in the medium.

Polarising angle of a transparent medium is 60^(@) , angle of refraction will be

The critical angle of a certain medium is 40.2^(@) . The speed of light in that medium is

The relationship between Brewester angle theta and the speed of light 'v' in