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The resistivity of a potentiometer wire ...

The resistivity of a potentiometer wire is `40xx10^(-8)Omega-m` and its area of cross section is `8xx10^(-6)m^(2)`. If 0.2 A current is flowing through the wire the potential gradient will be

A

`10^(-1)V//m`

B

`10^(-2)V//m`

C

`10^(-3)V//m`

D

`10^(-4)V//m`

Text Solution

Verified by Experts

The correct Answer is:
B
`R=(rhol)/(A)`
`therefore R/l=(rho)/(A)=(40 xx 10^(-8))/(8 xx 10^(-6))=5xx 10^(-2)`
`(V)/(l)=(IR)/(l)=0.2 xx 5 xx 10^(-2) =10^(-2)V//m`.
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