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A ray is incident at an angle 38^(@) an ...

A ray is incident at an angle `38^(@)` an a mirror. The angle between normal and reflected ray is

A

`38^(@)`

B

`52^(@)`

C

`90^(@)`

D

`76^(@)`

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The correct Answer is:
To solve the problem step by step, we will use the law of reflection which states that the angle of incidence is equal to the angle of reflection. ### Step-by-Step Solution: 1. **Understanding the Given Information**: - The angle of incidence (i) is given as 38 degrees with respect to the mirror surface. 2. **Identifying the Normal**: - The normal is an imaginary line that is perpendicular to the surface of the mirror. - Since the angle of incidence is measured from the mirror surface, we need to find the angle of incidence with respect to the normal. 3. **Calculating the Angle of Incidence**: - The angle between the mirror surface and the normal is 90 degrees. - Therefore, the angle of incidence (i) can be calculated as: \[ i = 90^\circ - 38^\circ = 52^\circ \] 4. **Applying the Law of Reflection**: - According to the law of reflection, the angle of incidence is equal to the angle of reflection (r): \[ i = r \] - Thus, we have: \[ r = 52^\circ \] 5. **Finding the Angle Between Normal and Reflected Ray**: - The angle between the normal and the reflected ray is the angle of reflection (r), which we found to be 52 degrees. ### Final Answer: The angle between the normal and the reflected ray is **52 degrees**. ---

To solve the problem step by step, we will use the law of reflection which states that the angle of incidence is equal to the angle of reflection. ### Step-by-Step Solution: 1. **Understanding the Given Information**: - The angle of incidence (i) is given as 38 degrees with respect to the mirror surface. 2. **Identifying the Normal**: ...
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