The polarising angle for a medium is `68^(@)`. What is the critical angle id the ray passes from medium to air ?

Options

A. `40^(@)`
B. `24^(@)`
C. `41.4^(@)`
D. `48.3^(@)`

Answer

B

Explanation

`mu = tan theta_(P) = (1)/(sin c)`
`:. sin c = (1)/(tan theta_(P))`
`:. c = sin((1)/(tan 68)) = sin^(-1) (0.4039) = 24^(@)`