The diamond has refractive index of 2.4 for sodium light of wavelength 5893 Å in air. The speed and wavelength of this light in diamond are

Options

A. `2.25 xx 10^(8)m//s, 2455 Å`
B. `1.25 xx 10^(8)m//s, 1455 Å`
C. `1.25 xx 10^(8)m//s, 2455 Å`
D. `2.25 xx 10^(8)m//s, 2355 Å`

Answer

C

Explanation

`lambda_(d) = (lambda_(a))/(mu_(d)) = (5893)/(2.4) = 2455 Å`
`v_(d) = (v_(a))/(mu_(d)) = (3 xx 10^(8))/(2.4) = 1.25 xx 10^(8) m//s`