The change in the wavelength of light when it travels from air to glass of refractive index 1.5 and the frequency of light `4 xx 10^(14) Hz` is

Options

A. 2500 Å
B. 2000 Å
C. 1500 Å
D. 3500 Å

Answer

A

Explanation

`lambda_(a) = (v_(a))/(n) = (3 xx 10^(8))/(4 xx 10^(14)) = 0.75 xx 10^(-6) = 7500 Å`
`lambda_(g) = (lambda_(g))/(mu_(g)) = (7500)/(1.5) = 5000 Å`
`lambda_(a) - lambda_(g) = 7500 - 5000 = 2500 Å`