A beam of light is incident on a water surface of angle of incidence `60^(@)` and R.I. of water is 4/3. The ratio of width of incident wavefront to refracted wavefront is

Options

A. `0.66`
B. `0.16`
C. `1.16`
D. `2.66`

Answer

A

Explanation

`mu = (sin i)/(sin r)`
`sin r = (sin r)/(mu) = (sin 60)/(4//3) = 0.6495`
`:. R = 40^(@)30'`
`:. (AB)/(CD) = (cos i)/(cos r) = (cos 60)/(cos 40^(@)30') = (0.5)/(0.7604)`