The change in wavelenght of light of frequency `4 xx 10 ^(14)`Hz. When it pass from air to glass, is `( mu_("glass") = 1.5)`

Options

A. 2500 Å
B. 3500 Å
C. 3000 Å
D. 2000 Å

Answer

A

Explanation

`lambda_(a) = (v_(a))/(n) = (3 xx 10^(8))/(4 xx 10^(14)) = 0.75 xx 10^(-6) = 7500 Å`
`lambda_(g) = (lambda_(g))/(mu_(g)) = (7500)/(1.5) = 5000 Å`
`lambda_(a) - lambda_(g) = 7500 - 5000 = 2500 Å`