A ray of light is incident on a medium boundry at polarising angle such that its deviation is `24^(@)`, then angle of incidence is :

Options

A. `24^(@)`
B. `57^(@)`
C. `66^(@)`
D. `90^(@)`

Answer

B

Explanation

`delta = 24^(@), I = ?`
`delta = i-r' = 24` …(1)
Now `i+r = 90` …(2)
`:.` Adding `eq^(n)` (1) and `eq^(n)` (2) we have
`2i = 114 " " :. i = 57^(@)`