Interference fringes are obtained due to the interference of wave from two coherent sources of light with amplitudes `a_(1)` and `a_(2)(a_(1)=2a_(2))`. The ratio of the maximum and minimum intensities of light in the interference pattern is

Options

A. `2:1`
B. `4:9`
C. `9:1`
D. `9:4`

Answer

C

Explanation

`(I_("max"))/(I_("min"))=((a_(1)+a_(2))^(2))/((a_(1)-a_(2))^(2))=((2a_(2)+a_(2))^(2))/((2a_(2)-a_(2)))=(9)/(1)`