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If in Young's experiment the distance be...

If in Young's experiment the distance between the two slits is doubled and the distance of the screen and slite is halved the fringewidth

A

is doubled

B

becomes 4 times

C

remains the same

D

becomes one fourth

Text Solution

Verified by Experts

The correct Answer is:
D

`d_(2)=2d_(1) D_(2)=(D_(1))/(2), beta _(2)= ?`
`beta prop =(D)/(d)`
`beta =(D_(2))/(D_(1))xx(d_(1))/(d_(2))`
`beta_(2)=(D_(1))/(2xxD_(1))xx(d_(1))/(2d_(1))xx beta_(1)=(beta_(1))/(4)`
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