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Two slits at a distance of 1mm are illum...

Two slits at a distance of `1mm` are illuminated by a light of wavelength `6.5xx10^-7m`. The interference fringes are observed on a screen placed at a distance of `1m`. The distance between third dark fringe and fifth bright fringe will be

A

`0.65 mm`

B

`1.265 mm`

C

`3.25 mm`

D

`4.88 mm`

Text Solution

Verified by Experts

The correct Answer is:
B
`x_(5b)-x_(3d)=(D)/(d)5lambda-(D)/(d) lambdaxx2.5`
`=2.5 (D)/(d)`
`=(2.5xx1xx6.5xx10^(-7))/(1xx10^(-3))`
`=1.6..25 mm`
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