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In a double slite experiment, the distan...

In a double slite experiment, the distance between the slit is `0.05 cm and` screen is 2 m away from the slits. The wavelength of light is `6xx10^(-5)` cm. The distance between the two successive bright fringes is

A

`0.24 cm`

B

`2.21 cm`

C

`1.28 cm`

D

`0.12 cm`

Text Solution

Verified by Experts

The correct Answer is:
A

`beta=(D)/(d) lambda`
`=(2xx6xx10^(-5))/(0.05xx10^(-2))`
`=0.274xx10^(-2)m`
`0.24 cm`
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