In Young's double-slit experiment using ...

In Young's double-slit experiment using `lambda=6000 Å`, distance between the screen and the source is 1m. If the fringe-width on the screen is 0.06 cm, the distance between the two coherent sources is

`0.01 mm`

1 cm

`0.1` mm

1 mm

Text Solution

Verified by Experts

The correct Answer is:

`d=(D)/(beta)lambda=(1xx6xx10^(-7))/(0.06xx10^(-2))= 1mm`

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